Riddles - come in and see if you can solve them!

Posted: Thu Apr 10, 2008 1:45 am

1. 2 fathers and 2 sons = 1 grandfather + 1 father + 1 grandson = 3 people

2. I dunno
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Posted: Thu Apr 10, 2008 1:50 am



Thats easy there are just three people, the grandfather,the father and the son,

2 Fathers & 2 Sons= the grandfather is a FATHER and he has a SON,his son is a FATHER who has a SON
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Posted: Thu Apr 10, 2008 11:52 am

The missionary said
"I will be burned to death"
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Posted: Thu Apr 10, 2008 1:04 pm

caspian got number 1 first,
and
yukino got number 2 first!

i got those riddles from the back of a preserved champorado carton. hehe.

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Posted: Sat Apr 12, 2008 2:43 pm

this is a freakishly hard situational riddle;
lets see if any of you can answer it.. heheheheh ^^

there are two rooms. You are in one of them. In the room that you are in are three switches, one of the switches lights a lamp inside the other room across the hall. Now, without any help of somekind, just you, the switches, the 2 rooms the hallway and the doors. How will you determine which of the 3 switches turns on the lamp, if once you get out of the first room, it shuts and you can never enter it again.?

gudluck.! ^^
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Posted: Sat Apr 12, 2008 3:13 pm

1] Open the door
2] Don't go out
3] Flick the switches
4] Observe the lamp
5] ???
6] PROFIT!!!
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Posted: Sat Apr 12, 2008 4:37 pm

IF the other room's door is open, I'd do what Yukino would do. javascript:emoticon('')
Laughing
If it was closed, I'd say you open the door to your room, and flip the switches and see when light comes from the other room. The other room is across from you after all.javascript:emoticon('')
Bleh!
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Posted: Sat Apr 12, 2008 4:55 pm

ahaha not quite, the other room's door is closed so you won't be able to see anything, not even the little light coming from the bottom of the door. and besides you can only open the door if your gonna go out, nothing like what Mr. Yuki said... hehehe

think think think.! ^^

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Posted: Sun Apr 13, 2008 10:04 am

Lawl I thought it was that easy.
Fine.

1] Open two of the switches. Leave one untouched.
2] Wait some time.
3] Close one of the two switches.
4] Go to the other room
5] Check the bulb
- If it is lighted, then the one you left on is the switch
- If it is warm but not lighted, then the one you closed is the switch
- If it is cold, then the one you left alone is the switch
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Posted: Mon Apr 14, 2008 11:09 pm

ROFL, you just snatched my next solution out of my mouth!

Now that I think about it, I think that I've seen a riddle like this in a book somewhere before.
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Posted: Tue Apr 15, 2008 12:11 pm

Accidental >.<

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Posted: Mon Apr 21, 2008 4:55 pm

you have two eggs. you need to figure out how high an egg can fall from a 100 story building before it breaks. the eggs might break from the first floor, or might even survive a drop from the 100th floor -- you have no a priori information. what is the largest number of egg drops you would ever have to do to find the right floor? (i.e. what's the most efficient way to drop the eggs and determine an answer?) you are allowed to break both eggs, as long as you identify the correct floor afterwards.



and here's another:

You are wearing a blindfold and thick gloves. An infinite number of quarters are laid out before you on a table of infinite area. Someone tells you that 20 of these quarters are tails and the rest are heads. He says that if you can split the quarters into 2 piles where the number of tails quarters is the same in both piles, then you win all of the quarters. You are allowed to move the quarters and to flip them over, but you can never tell what state a quarter is currently in (the blindfold prevents you from seeing, and the gloves prevent you from feeling which side is heads or tails). How do you partition the quarters so that you can win them all?


MOD EDIT:
In regards to the second riddle, the riddle states there are "infinite" quarters. You can partition any way you choose, e.g. "these three are one pile, the rest are the other". Allocating this "infinite" expanse as a pile is acceptable so long as you have two separate piles.

I can give hints for either as people deem necessary. (post or via singular messages so as not to force everyone into a hint)

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Posted: Tue Apr 22, 2008 3:52 am

1st riddle:
Hmm.. I'm thinking binary search. But that is risky.
Err.
Let X be my answer.
That means X is the no. of times I have to drop the egg [in turn, the floor which I first drop the egg]. If I drop the first egg at X and it breaks, I have (X-1) drops left. If it breaks at the second drop, then my second egg will have (X-2) drops left.

Putting it to an algorithm..
answer = 0;
for(a = 0; X - a != 0; a++) {
temp = X - a;
answer = answer + temp;
}

In equation..
[X(X+1)]/2 >= 100 <- no. of floors


so X = 14. I have to drop the egg at the 14th floor first.
I can do it in 14 tries.
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Posted: Wed Apr 23, 2008 1:22 pm



*jaws wide open*
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Posted: Wed Apr 23, 2008 1:23 pm

It's a relatively tricky algebra problem. *shrug*

I suppose I could answer the second riddle already but..

XD
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